Geometry help please?

Question

anonymous · Answer

attachment

anonymous · Answer

i only need help with the first and 2nd one please!

anonymous · Answer

@Owlcoffee @xxDragoonxx @happy_to_help if any of you guys knows this stuff pleas help!

happy_to_help · Answer

2c.36
2d.96

anonymous · Answer

yeah i already knew those 2 thanks, do you know 2a and 2b or 1? @happy_to_help

happy_to_help · Answer

No soryy.

anonymous · Answer

i already figured out 2) all i need is 1 and 3 @Owlcoffee

owlcoffee · Answer

To find the ordered pair of "L' " you'll have to multiply the coordinates of "L" by 1/4

anonymous · Answer

so what does that mean exactly lol, sry im not good at geometry

anonymous · Answer

do you know what #3 is?

owlcoffee · Answer

Like this, if L has coordinates (-4,-6), we can find the ordered pair in the new hexagon by doing the multiplication of 1/4 on the x and the y coordinates of the point, which means:
$$L'([\frac{ 1 }{ 4 }(-4)],[\frac{ 1 }{ 4 } -6]) $$

owlcoffee · Answer

Sorry, it has to multiply:
$$L'[(\frac{ 1 }{ 4 }(-4)),\frac{ 1 }{ 4 }(-6)]$$

anonymous · Answer

ok , so what do i do next?

owlcoffee · Answer

operate the multiplications.

anonymous · Answer

i have no idea what youre saying im sorry lol i just started taking geometry and i dont get any of it, do you mean solve that equation that you gave me?

owlcoffee · Answer

It's no equation, it's the representation of the dilated point, it would look like this:
$$L'(\frac{ (-4) }{ 4 }, \frac{ (-6) }{ 4 })$$

anonymous · Answer

oh ok gotcha, so how do we find the ordered pair

owlcoffee · Answer

L' is the ordered pair.