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yes, but the only change I would make is to write 0.1666 as 1/60 instead
*0.01666
watch your notation, the summation of 1/3 is 1/3
are we looking at the same question ??
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I posted #3
\[\sum_{i=1}^{4}\] is the total of those 4 partial sums
so I calculated all of them, then summed them in the end
Yes, your first calculation says \[\sum \frac{ 1 }{ 3 }\] which is 1/3, the summation of 1/3
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you did it correct, just the notation is slightly off
Oh okay okay. Thank you !
The first one is maybe, for i=1 \[f(x _{1},~y _{1}) = 1/3\]
not 1/3 sorry, the -10.67 you got
and you are finding the summation for i=1 to i=4 \[\sum_{i=1}^{4}f(x _{i}~,y _{i})\]
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goodluck
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