A driver in a car traveling at a speed of
75 km/h sees a cat 125 m away on the road.
How long will it take for the car to accelerate
uniformly to a stop in exactly 122 m?
Answer in units of s.
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OpenStudy (anikate):
any clue??
OpenStudy (anonymous):
@pooja195 Help me
OpenStudy (anonymous):
@pooja195 im new to helping
OpenStudy (anikate):
do u know the answer??
OpenStudy (anikate):
@DylanisNOW u know the answer??
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OpenStudy (anonymous):
Im trying to get @pooja195
OpenStudy (anikate):
i thuink she offline, but do know the answer to this question??
OpenStudy (anikate):
she appeears to be offline??
OpenStudy (anikate):
yea she offline
OpenStudy (anonymous):
Hold on...Im trying to figure it out. Please dont rush!
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OpenStudy (anikate):
ok
OpenStudy (anonymous):
@pooja195 No she isnt
OpenStudy (anikate):
ok, do u know how to do it though?
OpenStudy (anonymous):
Give me a sec please
OpenStudy (anikate):
ok np
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OpenStudy (anikate):
@pgpilot326 do u know how to do this? its a physics question
OpenStudy (anonymous):
Think of the units.
OpenStudy (anikate):
ok now?
OpenStudy (anonymous):
units are 75km/h right?
OpenStudy (anikate):
yes
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OpenStudy (anonymous):
Wait sorry hold on thats not it thats only 1
OpenStudy (anikate):
ok
OpenStudy (anonymous):
75km/h / 125 m=?
OpenStudy (anikate):
600m/h
OpenStudy (anonymous):
Okay do you have answer choices?
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OpenStudy (anikate):
nopee
OpenStudy (anikate):
do u havea roungh estimate of what the andswer could be??
OpenStudy (anonymous):
Think of it like this. Every second the speed decreases by?
OpenStudy (anonymous):
We cant give answers...Its just help to get you to understand it!
OpenStudy (anonymous):
Think of it like this. Every second the speed decreases by?
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OpenStudy (anikate):
the speed decreases by seconds(squared)
OpenStudy (anonymous):
Ok that is?
OpenStudy (anikate):
idk.....
OpenStudy (anonymous):
.... @pgpilot326 can you help me help him?
OpenStudy (anonymous):
Anyways..
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OpenStudy (anikate):
dylanis, can u just post a step by step explaination for it
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Step 1:units are 75km/h
OpenStudy (anonymous):
Step 2:75km/h / 125=600m/h
OpenStudy (anonymous):
Okay now we are at step 3
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OpenStudy (anonymous):
if a is a constant, integrate to get velocity and again to get position.
the velocity should be linear and the position a quadratic.
OpenStudy (anonymous):
since you know the initial and final speed you should be able to calc. the time
OpenStudy (anonymous):
pgpilot should we make a equation?
OpenStudy (anonymous):
should make 2 equations... velocity and position. you'll need both.
OpenStudy (anikate):
can you please show bothh?
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OpenStudy (anikate):
and solve with steps please?
OpenStudy (anonymous):
\[v \left( t \right)=v_0+at\]and\[x \left( t \right)=x_0+v_0t+\frac{ 1 }{ 2 }at^2\]
OpenStudy (anonymous):
pg you are right good job btw :)
OpenStudy (anonymous):
at t=0, initial speed (\(v_0\)) is 75 km/h and initial position is 0 m.
at t=\(t_1\), final speed (\(v_f\)) is 0 km/h and final position is 122 m.
OpenStudy (anonymous):
you need to solve for \(t_1\)
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