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Chemistry 20 Online
OpenStudy (anonymous):

A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ___ atm

OpenStudy (rushwr):

\[P _{total} = P _{He} + P _{Ne}\] Partial pressure of a gas = molar fraction x total pressure

OpenStudy (anonymous):

How do i find the molar fraction?

OpenStudy (rushwr):

Molar fraction = no. of moles of one component divided by the total no. of moles of all the compounds in the mixture

OpenStudy (rushwr):

The molar fraction of Ne would be \[\frac{ 0.56mol }{ (0.56 + 0.32)mol }\]

OpenStudy (anonymous):

Awesome! so then i take that times 0.95?

OpenStudy (rushwr):

yep

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