Question

PLEASE HELP
Find the number of real solutions to the functions below by graphing.
7) x + 3 = (x – 5)^2
8) x4 = x – 1
9) x3 = 5 – x

Answer 1

the first one you can maybe think of it as intersection points for the line x + 3
and the parabola (x-5)^2

Answer 2

or you can graph the parabola, and show where it crosses the x axis

Answer 3

ax^2+bx+c = 0

Answer 4

7) goes to x^2 -11x +22 =0 ,

Answer 5

im allowed on use the sight https://www.desmos.com/calculator to graph it will you help me so i know what to type in each box im sorry im horrible at math lol

Answer 6

graph that parabola y = f(x) and show the x values where y = f(x) = 0

Answer 7

k, for
7) graph y=x^2-11x+22
show the x values when y is zero (x-axis) those are the solutions

Answer 8

OR
Graph y=x+3 and y = (x-5)^2
and they should cross two times and have intersection points, the x values are the solutions

Answer 9

okay i graphed 7 thank you!

Answer 10

so how would i do numbers 8 and 9 now? im just confused on how to rearrange them like you did

Answer 11

show where x^4 - x + 1 crosses the x axis

Answer 12

y = x^4 - x + 1

if it even does

Answer 13

another approach
do a table with x values (common -3 to 3) calculate the corresponding y value
plot the points "see" the intersection

Answer 14

i think that is what they want, as @triciaal says,, just show how many times y = f(x) froses the x axis, number of roots, just "see" it

Answer 15

the point to know the general shape of each of those degrees

Answer 16

okay i graphed number 8 its correct thank you

Answer 17

no solution

Answer 18

what would number 7 be?