Which of the following represents the zeros of f(x) = x3 − 5x2 − 3x + 15?
5, square root of 3, −square root of 3
−5, −square root of 3, −square root of 3
5, −square root of 3, −square root of 3
−5, square root of 3, square root of 3
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\[x^2+3=0 \implies x^2=-3\]\[x= \pm i\sqrt{3}\]Your answer choices are kind of weird.
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OpenStudy (anonymous):
so its A then right
OpenStudy (jhannybean):
Oh I think Im the one that made the mistake.
OpenStudy (anonymous):
wait how
Parth (parthkohli):
yes it's x^2 - 3
OpenStudy (anonymous):
so it would still be A then right
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Parth (parthkohli):
ya
OpenStudy (anonymous):
ok thank you
OpenStudy (anonymous):
do you mind helping me with one more?
OpenStudy (anonymous):
@Jhannybean
@ParthKohli
OpenStudy (jhannybean):
correction: \((x^2-3)(x-5)=0\)
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OpenStudy (jhannybean):
It wouldnt let me post. -_-
Parth (parthkohli):
i know that feel
OpenStudy (anonymous):
Which of the following represents the zeros of f(x) = x3 − 14x2 + 61x − 84?
7, 4, −3
7, 4, 3
7, −4, −3
7, −4, 3
OpenStudy (anonymous):
i believe it would be B
Parth (parthkohli):
Look at the choices. We know that \(7\) is definitely a zero. Divide the thing by \(x - 7\). The remaining is a quadratic polynomial that can be factored.
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Parth (parthkohli):
or just plug in the choices lol idk who cares
Parth (parthkohli):
Vieta's Formulas @Jhannybean :)
OpenStudy (anonymous):
(x - 3) • (x - 4) • (x - 7)
OpenStudy (anonymous):
i got this
OpenStudy (anonymous):
so would it be B
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OpenStudy (jhannybean):
=__=.... VF. How would that work here? we have one root = \((x-7)\)
Then we'd find \(\alpha +\beta \) and \(\alpha\beta\) ?