Question

Will Fan and Medal!!!

(√5-x)
--------- = ?????
(√x+5)

Answer 1

no0 the answer choices are
A. {x|x<5}

Answer 2

^^ the attachment are the answer choices

Answer 3

@pooja195 we need you

Answer 4

is your function: \(\dfrac{\sqrt{5-x}}{\sqrt{x+5}}\) ?

Answer 5

yes

Answer 6

\[\frac{\sqrt{5-x}\cdot \sqrt{x+5}}{\sqrt{x+5} \cdot \sqrt{x+5}}\]\[=\frac{\sqrt{25-x^2}}{x+5}\]

Answer 7

Im not too sure what you're looking for. Maybe you can specify your question. Are we looking for where x has a vertical asymptote?

Answer 8

idk i just have the questiona dn the answers

Answer 9

Here is the whole thing

Answer 10

@Jhannybean

Answer 11

@ganeshie8

Answer 12

@Jhannybean @phi @Nnesha @ganeshie8 plz help

Answer 13

Hold on

Answer 14

@millsemily ok
@ganeshie8 help?

Answer 15

the domain are the "x" values you can use in your function and get a valid answer out.
You can run into trouble if you divide by 0 (that is not allowed) or taking the square root of a negative number (that is not allowed, if we want real numbers for the answer)

Normally, we would figure out what x values will cause trouble, and "not allow them"
what is left over is the domain.

Answer 16

First, look at the bottom
\[ \sqrt{x+5} \]
if that is 0, we would be dividing by 0 , and we don't allow that.
notice if x=-5 we get sqr(0)= 0. we x=-5 is not allowed

Answer 17

still looking at the bottom:
\[ \sqrt{x+5} \]
if x is less than -5, for example -6 we would have
\[ \sqrt{-6+5}= \sqrt{-1} \]
and we do not allow taking the square root of a negative number

so we now know \( x\le -5\) is not allowed
what is allowed is \( x \gt -5\)

next, look at the top
\[ \sqrt{5-x}\]
if x is bigger than 5, we will get a negative number inside the square root, and that is not allowed.
so x must be less than or equal to 5

we have
\[ -5 \lt x \le 5\]

Answer 18

ok thanls so much @Nnesha

Answer 19

what ??? o.O

Answer 20

For helping me understand the problem thanks @Nnesha