Solve for x. −ax + 3b 5 x the quantity 3 times b minus 5 all over a x the quantity 5 minus 3 times b all over negative a x

Question

Solve for x. −ax + 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a

misty1212 · Answer

hi!!

misty1212 · Answer

i will provide the answer for you so long as you tell me where this question comes from (my guess FLVS)

gibbs · Answer

x<−5−3b/a

misty1212 · Answer

because in fact you cannot solve an absolute value inequality with variable coefficients

misty1212 · Answer

@gibbs  is straight up wrong

anonymous · Answer

Its from FLVS @misty1212

misty1212 · Answer

ok lets solve it the way they want you to, even though it is wrong

anonymous · Answer

ok

misty1212 · Answer

$$−ax + 3b > 5$$ subtract $3b$ get $$-ax>5-3b$$ then divide by $-a$

misty1212 · Answer

now here is the mistake
they want you to change the inequality, because they want you to think that $-a$ is negative
that is sheer nonsense you do not know if $-a$ is negative or positive

misty1212 · Answer

in any case they want you to write $$x<\frac{5-3b}{-a}$$ or $$x<\frac{3b-5}{a}$$

misty1212 · Answer

it is totally incorrect, you should write them and tell them that anyone who thinks $-a$ is negative (because it has a  minus sign) does not understand what a variable is and has no business trying to teach math or write math questions

anonymous · Answer

My answers ar this though... x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a @misty1212