Question

Please answer this math logic question which I will send a picture of.

Answer 1

@mitchal

Answer 2

B cause as long the equation stays the same on both side it stays true and shwo that negated equation.

Answer 3

Wait what...

Answer 4

let me work on it again i might have misread it

Answer 5

Ok

Answer 6

The want you to prove the statement using "proof by contradiction"

Start with the statement
\[ 2(10x+3) \ne 5 (4x-3) \]
Proof by Contradiction:
Assume the statement is false, and that
\[ 2(10x+3) = 5 (4x-3) \]
now distribute the 2 on the left side and distribute the 5 on the right side
20x + 6= 20x-15
add -20x to both sides

what do you get ?

Answer 7

Well since you add -20x to each side it zeros out both 20x making it 6=-15?

Answer 8

Is that right or am i confused?

Answer 9

ohhh i see what i did wrong...i kept screwing up on the c step -_-

Answer 10

yes. and 6 does not equal -15. this is a contradiction.
Therefore the assumption we started with that
2(10x+3)=5(4x−3)
is not true, and therefore it must be
\[ 2(10x+3) \ne5(4x−3)\]
and we have proved the statement by contradiction

Answer 11

Ok thanks Phi :)

Answer 12

You too Mitchal