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Given that h(x)=x^2g(x) and g(3)=5 and g'(3)=7 find h'(3)
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You can use the product rule. h'(x) = f(x)g'(x) + g(x)f'(x) where in this problem f(x) = x²
so f(x)=x^2 and f'(x)=2x
right
then evaluate them both at 3
what about g(x) and g'(x)?
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well they're asking for h'(3), so you don't need g(x) and g'(x) since they gave you the values at 3.
so how would you use the product rule?
Above is the product rule generally. Specifically at x = 3. \[h'(3) = f(3)g'(3) + g(3)f'(3)\]
g(3) and g'(3) are given. f(3) and f'(3) are found by evaluating x² and 2x at 3 respectively
oh is it h'(3)=9*7+5*6
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f(3) = 3² = 9 f'(3) = 2(3) = 6
yep exactly
so the answer is 93
thanks for your help peachpi
yes that's right. You're welcome
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