From a class of 14 boys and 9 girls, how many ways can I choose a committee of 6 to analyze classroom productivity with and equal number of boys and girls? a) 30,576 b)252,252 c)48 d)126
Don't quote me on this but I think it is D. 126....
ok thanks
Your Welcome, good Luck! :)
for some reason i think its choice a but I'm not 100% sure.can anyone else help?
ASAP
please anyone help asap. I don't need a too detailed answer
The number of ways to choose 3 girls from 14 girls is 14C3. Each of these ways can be combined with each of the 9C3 ways of choosing 3 boys from 9 boys. Therefore the total number of ways of choosing 6 students with equal numbers of boys and girls is given by: \[\large 14C3\times9C3=\frac{14\times13\times12}{6}\times\frac{9\times8\times7}{6}=you\ can\ calculate\]
that's not one of the answer choices which is odd because it looks right
What did you get for each of the fractions?
i got the same as you to be honest but it wasn't one of the answer choices so i thought i did it wrong
But what did you get for each of the fractions?
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