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Mathematics 12 Online
OpenStudy (anonymous):

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch? 4/11 7/11 3/11 2/3

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

@triciaal

OpenStudy (anonymous):

Are these ratios?

OpenStudy (anonymous):

idk thats all the question says

OpenStudy (anonymous):

okay well if jenny gets to choose lunch if she chooses a carnation or a rose. How many flowers are either a carnation or a rose?

OpenStudy (anonymous):

23?

OpenStudy (anonymous):

No.... if their are 4 roses and 3 carnations how many is that together?

OpenStudy (anonymous):

my bad they are ratios so 4/11?

OpenStudy (anonymous):

No but when you put the carnations and roses together you have 7 flowers that are either carnations or roses correct?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So as you already said when you said 4/11 you were saying that their are 11 flowers in the whole bouquet.

OpenStudy (anonymous):

so its 7/11

OpenStudy (anonymous):

yes, that's what i would say is correct as long as you can't simplify it and from what i can tell you cant.

OpenStudy (anonymous):

thankyou it was right

OpenStudy (anonymous):

Your welcome glad I could help

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