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Chemistry 20 Online
OpenStudy (mortonsalt):

Hello everyone! I was wondering if anyone can help me with this question? Picture attached.

OpenStudy (mortonsalt):

OpenStudy (mortonsalt):

\[\lambda=\frac{hc}{E_{ph}}\] right?

OpenStudy (mortonsalt):

Do I get the difference of eV, e.g. like when n=2 goes to n=1, eV=-13.6-(-3.4)?

OpenStudy (cuanchi):

the lowest the electron fall the higher is the energy that release, the higher the energy the lower the wavelength. If an electron fall from any level to the level 1 will release the most energy (lower wavelength), then if it felt from the 6 to the 1 release more energy than if it fell from the 5. And if it felt from the 5 to the 1 release more than if does from the 4 to the 1. Then if an electron fall to the n=2 wherever level is coming from will always release less energy that any other electron falling to the n=1

OpenStudy (cuanchi):

4 ->3 4 ->2 2 ->1 3 -> 1

OpenStudy (mortonsalt):

Thank you so much! I understand it now.

OpenStudy (cuanchi):

Yes you can replace the values in the formula and calculate the wavelenght

OpenStudy (mortonsalt):

Thank you! @Cuanchi

jaynator495 (jaynator495):

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