Mathematics
15 Online
OpenStudy (anonymous):
let g(x)=|cos x-1|. the maximum value attained by g on the closed interval [0,2pi] occurs at x equal to:
a. -1
b. 0
c. pi/2
d. 2
e. pi
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OpenStudy (welshfella):
what is the range of cos x?
OpenStudy (anonymous):
0,2?
OpenStudy (welshfella):
no, cos 0 and cos 2pi = 1 , cos pi = -1
OpenStudy (welshfella):
remember the vertical lines mean the absolute value which is positive
OpenStudy (anonymous):
so -1
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OpenStudy (anonymous):
wait could it be zero 1-1
OpenStudy (welshfella):
no
OpenStudy (welshfella):
try putting values of cos x into the expression until you get maximimum value of g
OpenStudy (anonymous):
2
OpenStudy (welshfella):
|-1-1| = |-2| = 2 Thats the maximum value of g
what value of x will give that?
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OpenStudy (welshfella):
cos x must equal - 1 right?
so x = ?
OpenStudy (anonymous):
-1
OpenStudy (welshfella):
no cos x = -1
what value of x , in radians, will give cos x = -1?
OpenStudy (welshfella):
the question asks for value of x , not cos x.
OpenStudy (anonymous):
0
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OpenStudy (welshfella):
look at my second post
OpenStudy (anonymous):
1
OpenStudy (welshfella):
no
OpenStudy (anonymous):
pi
OpenStudy (welshfella):
the cos of what angle is -1?
check it out with ur calculator
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OpenStudy (welshfella):
yes its pi because cos pi = -1
OpenStudy (welshfella):
do you follow it now?
OpenStudy (anonymous):
yes i do thanks:)