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Mathematics 15 Online
OpenStudy (anonymous):

let g(x)=|cos x-1|. the maximum value attained by g on the closed interval [0,2pi] occurs at x equal to: a. -1 b. 0 c. pi/2 d. 2 e. pi

OpenStudy (welshfella):

what is the range of cos x?

OpenStudy (anonymous):

0,2?

OpenStudy (welshfella):

no, cos 0 and cos 2pi = 1 , cos pi = -1

OpenStudy (welshfella):

remember the vertical lines mean the absolute value which is positive

OpenStudy (anonymous):

so -1

OpenStudy (anonymous):

wait could it be zero 1-1

OpenStudy (welshfella):

no

OpenStudy (welshfella):

try putting values of cos x into the expression until you get maximimum value of g

OpenStudy (anonymous):

2

OpenStudy (welshfella):

|-1-1| = |-2| = 2 Thats the maximum value of g what value of x will give that?

OpenStudy (welshfella):

cos x must equal - 1 right? so x = ?

OpenStudy (anonymous):

-1

OpenStudy (welshfella):

no cos x = -1 what value of x , in radians, will give cos x = -1?

OpenStudy (welshfella):

the question asks for value of x , not cos x.

OpenStudy (anonymous):

0

OpenStudy (welshfella):

look at my second post

OpenStudy (anonymous):

1

OpenStudy (welshfella):

no

OpenStudy (anonymous):

pi

OpenStudy (welshfella):

the cos of what angle is -1? check it out with ur calculator

OpenStudy (welshfella):

yes its pi because cos pi = -1

OpenStudy (welshfella):

do you follow it now?

OpenStudy (anonymous):

yes i do thanks:)

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