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ya is correct
they are basically asking you to solve \(3(x+2) - 4=2\)
when you `solve for the inverse function`, you swap x and y, then solve for y so when you plug x = 2 into the inverse, you are really plugging in y = 2 into the original
did you solve \(3(x+2) - 4 = 2\) for x?
Let's check your answer 3(x+2) - 4 = 2 3(8+2) - 4 = 2 ... replace x with 8 3(10) - 4 = 2 30 - 4 = 2 26 = 2 ... this equation is false, so x = 8 is not the solution
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scroll back up. I explain how you actually replace y with 2
f(x) = 3(x+2) - 4 is the same as y = 3(x+2) - 4
y = f(x)
I think is y=mx-b
yep x = 0 makes 2 = 3(x+2) - 4 true
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no problem
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