9|9-8x|=2x+3 Please explain the steps to completing. I will medal and fan!
@satellite73
you have to solve two equations i think
for \(x>\frac{9}{8}\) this is the same as \[9(9-8x)=2x+3\]
oh maybe i just screwed that up lets make it easiery
\[|9-8x|=|8x-9|\] so we can start with \[9|8x-9|=2x+3\]
now if \(x>\frac{9}{8}\) that is the same as \[9(8x-9)=2x+3\] which i guess you can solve
it is ugly, but you should get \(x=\frac{6}{5}\) i think
I'm still confused
lets back up and go slow
is this line \[|9-8x|=|8x-9|\] clear?
yes
ok now \(|8x-9|\) is one of two things if \(x> \frac{9}{8}\) then \(8x-9>0\) and if \(8x-9>0\) then \(|8x-9|=8x-9\) because it is positive
clear or not ?
clear
so if \(x>\frac{9}{8}\) you can go ahead and solve \[9(8x-9)=2x+3\]
that takes a bit of algebra, but i assume it is doable
if not, let me know
I don't know how to solve it @satellite73
multiply out and get \[72x-81=2x+3\]
Do i combine like terms now?
subtract \(2x\) get \[70x-81=3\] then add \(81\) to get \[70x=84\] and finally divide by \(70\) to get \[x=\frac{84}{70}=\frac{6}{5}\]
ooooooohhhhh ok thank you so much again!!!!
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