Question

What is the value of the following expression when x=3 and y=-2?

4x-y2

Answer 1

can you put those values into the expression

Answer 2

just the order of ops thing like last time i think

Answer 3

@jim_thompson5910

Answer 4

The expression is this right?

\[\Large 4x - y^2\]

Answer 5

yes!

Answer 6

to start off, replace every x with 3 (since x = 3)
\[\Large 4\color{red}{x} - y^2\]
\[\Large 4(\color{red}{3}) - y^2\]

Answer 7

Sorry brain fart. and I really don't know how to use this site.

Answer 8

Then replace every y with -2
\[\Large 4(3) - \color{red}{y}^2\]
\[\Large 4(3) - (\color{red}{-2})^2\]

Answer 9

at this point, you either use pen/paper to compute or a calculator to compute

Answer 10

Well 4*3 equals 64.

Answer 11

4*3 does not equal 64

Answer 12

you might be thinking of \(\Large 4^3\)

Answer 13

That's what I meant. How you drew it out before kind of like \[4*4*4\]

Answer 14

Something like that lol

Answer 15

well in the case of 4*3, it's simply 4 times 3, which is 12

Answer 16

that's different from 4^3, which is 4 to the third power

Answer 17

Oh ok!

Answer 18

btw, 4(3) is another way of saying 4*3

Answer 19

Oh ok!:)

Answer 20

Talking about the final answer. From my calulations, its positive?

Answer 21

The answer is positive. Yes

Answer 22

I stuck between 8 and 16.

Answer 23

what is (-2)^2 equal to?

Answer 24

-4? I have a feeling that that's incorrect.

Answer 25

we multiply -2 by itself twice

Answer 26

(-2)^2 = (-2)*(-2) = ??

Answer 27

-8?

Answer 28

you were correct about the 4 part, it's just positive and not negative

-2 times -2 = +4

Answer 29

negative times negative = positive

Answer 30

Oh!!!!!

Answer 31

\[\Large \color{red}{4(3)} - \color{blue}{(-2)^2}\]
\[\Large \color{red}{12} - \color{blue}{4}\]

Answer 32

8

Answer 33

yep

Answer 34

Thats the final answer?

Answer 35

yes it is