Question

Discriminant help?

Answer 1

Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

x^2 + 6x - 3 = 0

Answer 2

@Vocaloid

Answer 3

@ganeshie8

Answer 4

Do you know the formula for the discriminant?

Answer 5

In the general expression for a quadratic
\[\large ax^{2}+bx+c=0\]
the discriminant is
\[\large b^{2}-4ac\]
In the given quadratic, a = 1; b = 6 and c = -3
Now you just need to plug in these values.

Answer 6

6^2 - 4(1)(-3) ?

Answer 7

Correct.

Answer 8

my final answer would be 48?

Answer 9

Correct again.

Answer 10

at the end of the question it says " Then use the value to determine how many real number solutions each equation has."

Answer 11

The value of the discriminant is positive, but is not a perfect square. Therefore there are two real roots which are irrational and unequal.

Answer 12

Thats all i need to do right?

Answer 13

That is right.

Answer 14

Thank u.

Answer 15

You're welcome :)