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x+1/x+2=6 is given. Find (x+2)^2+1/(x+2)^2.
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\[\frac{ x+1 }{ x+2 } = 6\]
that right?
(x+1)/(x+2) = 6
\[x+\frac{ 1 }{x+2 }=6, (x+2)^2+\frac{ 1 }{ (x+2)^{2}}=?\]
solve the equation for x, then use that x in the expression to find a value
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\(\large \color{black}{\begin{align} & x+2+\frac{ 1 }{x+2 }=8, \hspace{.33em}\\~\\ \end{align}}\)
\(\large \color{black}{\begin{align} & put\ \ x+2=a \hspace{.33em}\\~\\ \end{align}}\)
ok thank you i could not think i should add 2 to both sides so the answer is 62
ans square both sides
that is clever! \(a+\frac{1}{a} = k \implies a^2+\frac{1}{a^2} = k^2-2\)
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yeah, looks like that was the point of the problem.. nice
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