Question

help

Answer 1

Find the value of the discriminant for the quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

3x^2 + 2x +1 = 0

Answer 2

@imqwerty

Answer 3

@ganeshie8

Answer 4

if u have any quadratic equation like this-\[ax^2+bx+c=0\]then the discriminant[D] is given by -\[D=b^2-4ac\]

so we have the equation-\[3x^2+2x+1 \]comparing it with the standard equation ax^2+bx+c=0
we can see that a=2, b=2, c=1

so substituting these values in the discriminant formula we get\[D=2^2-4(3)(1)\]\[D=4-12 => D=-8\]

the solutions x can be represented by-\[x=\frac{ -b \pm \sqrt{D} }{ 2a }\]but since D is negative root(D) doesn't exists so the roots are unreal

Answer 5

Thank you!

Answer 6

np :)

Answer 7

btw up there did you mean a = 3?

Answer 8

yep...a is 3. but it dosent change the outcome, still no real solutions

Answer 9

yes a=3

Answer 10

alright. thnx :)