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diana.xl · Answer

x^2+4x +4 = 0

diana.xl · Answer

@imqwerty

kittiwitti1 · Answer

What do you want to do with this equation?

imqwerty · Answer

1)compare this equation with$$ax^2+bx+x=0$$
2)identify a,b,c
3)apply this formula to find discriminant$$D=b^2-4ac$$

kittiwitti1 · Answer

$$x^{2}+4x+4=0\text{ Solve for x?}$$

diana.xl · Answer

x^2 + 4x +4 = 0
a = 1, b = 4, c = 4
D = 4x - 4(1)(4)

diana.xl · Answer

would my final answer be 0?

imqwerty · Answer

wait u wanna knw discriminant or roots?

diana.xl · Answer

yes i do. its just like the other question u answered.

kittiwitti1 · Answer

If you're solving for x then the quadratic formula would be of better use:$$x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$$

kittiwitti1 · Answer

What do you mean by your final answer then?

imqwerty · Answer

ok yes D=0 is correct

diana.xl · Answer

Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

diana.xl · Answer

this is what its asking

kittiwitti1 · Answer

Okay. Please post that next time because I got confused :p

diana.xl · Answer

haha ok

diana.xl · Answer

@imqwerty 

The quadratic equation will be having only one real root.?

kittiwitti1 · Answer

I suck at discriminants though so yeah ask the great qwerty ^^

imqwerty · Answer

back

imqwerty · Answer

yes because D=0 there is only 1 real root

diana.xl · Answer

ok thnx!!

imqwerty · Answer

np :)

diana.xl · Answer

can u help with one more?

imqwerty · Answer

yea y not

diana.xl · Answer

Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

5x^2 + x = 4

imqwerty · Answer

ok do the same steps

diana.xl · Answer

a = 5, b = 1, c = 4
D = 1 - 4(5)(4)
D = 81.

is it correct?

imqwerty · Answer

back

imqwerty · Answer

1st u need to convert the equation into this form-$$ax^2+bx+c=0$$so there shuld be a 0 on the left hand side can u bring a zero out there by subtracting 4 from both sides :)

diana.xl · Answer

i dont understand