Question

help

Answer 1

Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

2x^2 -3x = -5

Answer 2

@ganeshie8

Answer 3

the discriminant is -31 hold on i gotta do simplest form...

Answer 4

The discriminant is -31, using the formula ax^2 + bx + c = 0 (2x^2 + -3x + 5 = 0)
The simplest form of this equation, step by step -
Combine like terms: 2x^2 - 3x + 5 = 0
Apply the Quadratic Formula: \[-b + \sqrt{b^2-4ac} \over 2a \]
\[-b-\sqrt{b^2-4ac} \over 2a\]
So, in this equation, a = 2, b = -3, c = 5.
\[x = 3 + \sqrt{31} \over 4\] and \[3 - \sqrt{31} \over 4\]