Question

What is 36x^2-51x+18 factored?

Answer 1

start by factoring out 3

\[3[12x^2 - 17x + 6]\]

so looking at the quadratic... a never fail method for

\[ax^2 + bx + c\]

is to multiply a and c so you have

\[12 \times 6 = 72\]

find the factors of 72 that add to -17... both factors are negative.

any thoughts on the factors...?

Answer 2

3(3x−2)(4x−3)

Answer 3

there you go, someone always gives the answer... why not show your working...

Answer 4

Factors are -9 &-8

Answer 5

so then the expression is written as

(ax + factor 1)(ax + factor 2)
-------------------------
a

so your problem becomes

\[3 \times \frac{(12x -9)(12x -8)}{12}\]

now remove the common factors from the binomials

\[3 \times \frac{4(3x -2)3(4x - 3)}{12}\]

then cancel the common factors

leaving the answer posted above..

works every time a difficult quadratic can be factored...