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jimthompson5910 (jim_thompson5910):
we have a `y` in the first equation and a `-4y` in the second equation
adding them up gives: `y+(-4y) = -3y` which isn't 0 like we want
however we can change that `y` to `+4y` by multiplying by 4. Then notice how `4y + (-4y) = 0y = 0`
OpenStudy (anonymous):
so it's 0?
jimthompson5910 (jim_thompson5910):
to change the y to 4y, we have to multiply both sides of the first equation by 4
x+y=7
4*(x+y)=4*7
4x+4y = 28
jimthompson5910 (jim_thompson5910):
This system
x+y=7
2x-4y=8
turns into
4x+4y=28
2x-4y=8
jimthompson5910 (jim_thompson5910):
Do you see how to solve
4x+4y=28
2x-4y=8
??
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OpenStudy (anonymous):
i don't
OpenStudy (anonymous):
would you subtract?
jimthompson5910 (jim_thompson5910):
you add actually
jimthompson5910 (jim_thompson5910):
add straight down
4x+4y=28
2x-4y=8
-----------
6x+0y = 36
so 6x = 36 which means x = ???
OpenStudy (anonymous):
6
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
now take that x value and plug it into any equation that has x and y in it
jimthompson5910 (jim_thompson5910):
then solve for y
OpenStudy (anonymous):
12-47=8? am i doing that right?
OpenStudy (anonymous):
i mean 12-4y=8
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