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Mathematics 6 Online
OpenStudy (vera_ewing):

Math question

OpenStudy (vera_ewing):

jimthompson5910 (jim_thompson5910):

They want you to multiply 3 by that matrix

jimthompson5910 (jim_thompson5910):

Multiply the 3 by each term inside the matrix \[\large \color{red}{3*}\left[\begin{array}{cccc} -1 & 5 & 5 & -2\\ 2 & 5 & 3 & -4 \end{array}\right] = \left[\begin{array}{cccc} \color{red}{3*}(-1) & \color{red}{3*}5 & \color{red}{3*}5 & \color{red}{3*}(-2)\\ \color{red}{3*}2 & \color{red}{3*}5 & \color{red}{3*}3 & \color{red}{3*}(-4) \end{array}\right] =??\] Note: the final result will be a 2x4 matrix

OpenStudy (vera_ewing):

-3, 15, 15, -6 6, 15, 15, -12

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

the first column -1, 2 turns into -3, 6 so it's the same as multiplying the point (-1,2) by 3 to get (-3,6). Dilating it out 3 times further away from the origin

OpenStudy (vera_ewing):

Ok, so how can I tell which graph it is?

jimthompson5910 (jim_thompson5910):

each column of the matrix represents a point or ordered pair

jimthompson5910 (jim_thompson5910):

eg: first column -1,2 means we have the point (-1,2)

jimthompson5910 (jim_thompson5910):

well I can't see your answer choices

OpenStudy (vera_ewing):

A.

OpenStudy (vera_ewing):

B.

OpenStudy (vera_ewing):

C.

OpenStudy (vera_ewing):

D.

OpenStudy (vera_ewing):

@jim_thompson5910 It's A?

jimthompson5910 (jim_thompson5910):

one moment

jimthompson5910 (jim_thompson5910):

Probably the best thing you can do is just graph each point. What I did was graph using geogebra. That program has a lot of interactivity and flexibility, which is why I like it So you'd graph each column as its own point eg: W = (-1,2), X = (5,5), Y = (5,3), etc etc see the attached as for what you'd get in the graph

OpenStudy (vera_ewing):

Thanks so much!

jimthompson5910 (jim_thompson5910):

no problem

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