Question

help

Answer 1

Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has.

2x^2 -3x = -5

Answer 2

@ganeshie8

Answer 3

Hey!

Answer 4

hi

Answer 5

do you know the "standard form" of quadratic equation ?

Answer 6

2x^2 -3x = -5

would my equation be 2x^2 -3x +5 = 0?

Answer 7

Exactly!

Answer 8

Did you solve it out like they asked you to? I honestly forgot how to do this work because I'm now a sophomore in high school so...

Answer 9

compare that with \(\color{red}{a}x^2 + \color{red}{b}x +\color{red}{c}=0\)

Answer 10

\(\color{red}{a}=?\)
\(\color{red}{b}=?\)
\(\color{red}{c}=?\)

Answer 11

Oh wait, never mind! You've got your answer. Never mind, you're on the right track. Carry on.

Answer 12

a = 2, b = -3, c = 5

Answer 13

Very good!
next find the discriminant using the definition :
discriminant = \(b^2-4ac\)

Answer 14

simply plugin the values and simplify

Answer 15

D = -3 – 4 (2)(5)

Answer 16

*applauding*

Answer 17

D = (-3)^2 – 4 (2)(5)

Answer 18

*Great! You're an official mathematics genius!*

Answer 19

oh ok. would my final answer be -31?

Answer 20

Yes, so the discriminant is \(-31\), which is negative.
so how many real solution the given quadratic equation will be having ?

Answer 21

Since D is negative, root (D) doesn’t exist so the roots are unreal.

Answer 22

Awesome! so there are no real roots for the given quadratic equation

Answer 23

Okay so let me get this straight: So the asking person is asking this very confusing question which I DO NOT GET ANYMORE!!!! (Sorry for all caps). Ah... could someone teach me this stuff again? I know the powers pretty well but this particular problem like this. It's not like it's for homework anything but I really need help understanding this. I'm learning Geometry this year and I really just need some math help right now. Thanks!

Answer 24

Hey! What about me @Diana.xL? That's just unsportsman like!

Answer 25

@MeShipLad32 please open a new question and tag me
I'd be happy to assist you :)

Answer 26

nope im good