Question

Will medal please help.
consider g(n) = -12-2n/3.
Find g^-1(n)

Answer 1

@misty1212

Answer 2

@ganeshie8

Answer 3

@Jhannybean

Answer 4

Is your function : \(g(n) = \dfrac{-12-2n}{3}\)?

Answer 5

yes

Answer 6

we need to find the inverse.

Answer 7

So first graph it to see whether it's a one-to-one function, and it is. \[y = \frac{-12-2n}{3}\]Switch y and n \[n=\frac{-12-2y}{3}\]Now lets solve for y.

Answer 8

I let my function \(g(n) = y\)

Answer 9

What function do you get when you resolve for y?

Answer 10

3n + 12 = -2y

Answer 11

Good, and when you isolate y?

Answer 12

that's where i reached till, i don't know what to do after that

Answer 13

To isolate the variable y, what do you have to do to each side of the equation?

Answer 14

divide by 2 i guess

Answer 15

-2, and yes, you were partially right.

Answer 16

so 3n + 12/-2 = y

Answer 17

(3n + 12)/ -2 = y *

It helps when you put parenthesis () around the numerator and denominator

Answer 18

can I ask one more question please????

Answer 19

We can simplify that function a bit by dividing both terms in the numerator by -2.

((3n)/-2) +(12/-2) = y

Answer 20

Sure, I can try helping.

Answer 21

ok, find the inverse of the equation
f(x) = \[-\frac{ 4 }{ 7 }x - \frac{ 16 }{ 7 }\]

Answer 22

\[y=\frac{-4x-16}{7}\]Same process, we switch x and y. \[x=\frac{-4y-16}{7}\] and now we resolve for y.

Answer 23

7x +16 = -4x

Answer 24

right?

Answer 25

-4y*

Answer 26

ohh yeah

Answer 27

7x + 16 = -4y

and now we've got to isolate y, just like before.

Answer 28

\[\frac{ 7x+16 }{ -4 }\]

Answer 29

That's right, and after resolving for y, we relabel it as \(f^{-1}(x)\)

Answer 30

ok, can i ask further questions if i have doubt in them please?

Answer 31

Sure, but im logging off for a while, although good luck on learning this!`

Answer 32

when will you come back