Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (iwanttogotostanford):

HELP W? ACT PREP: The figure below shows 2 tangent circles such that the 10-centimeter diameter of the smaller circle is equal to the radius of the larger circle. What is the area, in square centimeters, of the shaded region? DRAWN BELOW

OpenStudy (iwanttogotostanford):

|dw:1443385130601:dw|

zepdrix (zepdrix):

Which part is shaded? :)

OpenStudy (iwanttogotostanford):

the larger circle only

zepdrix (zepdrix):

Inside the big circle, but outside the small one? ah ok

OpenStudy (iwanttogotostanford):

yep

zepdrix (zepdrix):

That's not too bad :) That's simply `the area of the big circle` - `area of the small circle`

zepdrix (zepdrix):

You'll have to recall your area formula: \(\large\rm A=\pi r^2\) What is the area of the larger circle? Are you able to figure that out based on the information given?

OpenStudy (iwanttogotostanford):

yes! so it would be two equations, one pi (10)^2 and then the other pi(10)^2?

zepdrix (zepdrix):

Ooo careful! :) They didn't actually tell us the `radius` of the smaller circle.

OpenStudy (iwanttogotostanford):

oh yeah ok so what do i do?

zepdrix (zepdrix):

You have to remember the relationship bebtween `diameter` and `radius`.

OpenStudy (iwanttogotostanford):

radius is half diameter

zepdrix (zepdrix):

Ok good :o Half of 10 is 5. So that gives us the `r` that we want to use for the smaller circle.

OpenStudy (iwanttogotostanford):

yes

zepdrix (zepdrix):

You had your first equation correct, which corresponded to the area of the larger circle \(\large\rm \pi(10)^2\)

zepdrix (zepdrix):

So the smaller one, which we've corrected, should be \(\large\rm \pi(5)^2\) ya? :o

OpenStudy (iwanttogotostanford):

yes

zepdrix (zepdrix):

Square those numbers, then subtract the smaller one from the larger one

OpenStudy (iwanttogotostanford):

i forget do i use pi in the equation orr just leave it until the end

OpenStudy (iwanttogotostanford):

ok nevermind for my final answer i got 75pi

zepdrix (zepdrix):

yay good job \c:/

OpenStudy (iwanttogotostanford):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!