What is y^4-y^3=0
How do you factor this out?

Question

nnesha · Answer

what's the common factor ?
well its soo easy to find common factor of variables 
`variable with the smallest degree would be the common factor `

anonymous · Answer

How would you do it though?

danjs · Answer

you are really multiplying by y^2 / y^2
this will pull a y^2 term out of each of those

nnesha · Answer

we should take out the common factor  
so first ) what's a  common factor ???

danjs · Answer

left with   y^2*(each divided by y^2)

anonymous · Answer

@DanJS my book did it by y(y^3-1) =y(y-1)(y^2+y+1) I dont understand how they do it

nnesha · Answer

well ^^take out y from y^4 -y^3 
 $$\huge\rm y(y^3-1)$$
y^3-1 is same as (y^3 -1^3)

nnesha · Answer

then you can apply the rule $$\huge\rm x^3-y^3=(x-y)(x^2+xy+y^2)$$

danjs · Answer

is the original problem 

y^4 - y^3

danjs · Answer

=  y^3 * (y-1) = 0

danjs · Answer

y is 0 or 1

anonymous · Answer

Yes

nnesha · Answer

i guess it's y(y^3-1)  ??

anonymous · Answer

Shouldn't it factor out as y^3(y-1)?

anonymous · Answer

Doesn't y(y^3-1) = y^4-y

nnesha · Answer

ye.......
and then set it equal to zero if you want to solve to for y
but factor is y^3(y-1) that looks correct 2 me :/

mathstudent55 · Answer

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