Question

Linear algebra...dealing with inner product and finding the smallest interior angle.
See attachments please...

Answer 1

That is the question and the answer that I came up with. It is obviously wrong because a triangle does not have 249.96 degrees on its interior. If you can point out what I am doing wrong I would appreciate it

Answer 2

so the subtraction is to define BC ?

Answer 3

3 2 -3
8 -1 1
-------
24-2-3 = 19 is our product of AB and AC

3 2 -3
3 2 -3
-------
9+4+6 = 19, sqrt(19)

8 -1 1
8 -1 1
------
64+1+1 = 66. sqrt(66)

cos(a1) = 19/sqrt(19*66)

a1 = 57.55 degrees

Answer 4

No if you look at the first attachment that was the problem. What is on the other attachment is me trying to work it out. If What I have is wrong tell me

Answer 5

ac.ab is messed up

Answer 6

my sqrt19 is messed up too ... add instead of multiplied

Answer 7

<ac,ab> is not 11 ; first value is 3, not 2

<ba,bc>, third term is 3(4) is not -12

you have some transcription errors and sign errors thruout that need addressed.

Answer 8

.

Answer 9

Yeah I made quite a few mistakes there let me try that again with the right numbers and see if it works