Question

Fill in the blank to make the expression a perfect square. V^2-14v+?

Answer 1

Hint: the first step is to divide 14 by 2

Answer 2

so 7

Answer 3

also: (a - b)^2 = a^2 - 2ab + b^2

Answer 4

is it49?

Answer 5

yea

Answer 6

yes + 49

Answer 7

Thank you!

Answer 8

yw

Answer 9

\[v^2+14v \implies ax^2+bx\] You want it in the quadratic form, \(av^2+bv+c\)
\[c=\left(\frac{b}{2}\right)^2 \qquad \therefore \qquad c=\left(\frac{4}{2}\right)^2 = (2)^2=4\]\[v^2+4v+4 \implies (v+2)^2\]