Question

An apartment complex contains 230 apartments each having 1, 2 or 3 bedrooms. The number of 2-bedroom apartments is 10 more than 3 times the number of 3-bedroom apartments. The number of 1-bedroom apartmenst is twice the number of 2-bedroom apartments. How many apartments of each kind are in the complex? Please answer with procedure

Answer 1

Let
x = number of 1-bedroom apartments
y = number of 2-bedroom apartments
z = number of 3-bedroom apartments

Answer 2

`The number of 2-bedroom apartments is 10 more than 3 times the number of 3-bedroom apartments`

gives the equation

y = 3z + 10

Answer 3

`The number of 1-bedroom apartmenst is twice the number of 2-bedroom apartments`

means

x = 2y

Answer 4

`An apartment complex contains 230 apartments each having 1, 2 or 3 bedrooms`

so

x+y+z = 230

Answer 5

you have this system of equations

\[\Large \begin{cases}y = 3z + 10\\x = 2y\\x+y+z = 230\end{cases}\]

Answer 6

Do you see how to solve?

Answer 7

Honestly i dont...

Answer 8

Its the only one i cant seem to get

Answer 9

since y = 3z+10, we can replace the y in x = 2y with 3z+10

x = 2y
x = 2*(3z+10) ... replace y with 3z+10
x = 6z+20

Answer 10

x+y+z = 230

6z+20+y+z = 230 ... replace x with 6z+20

6z+20+3z+10+z = 230 ... replace y with 3z+10

Answer 11

now solve `6z+20+3z+10+z = 230` for z

Answer 12

omg thanks brother
You helped me out a lot today

Answer 13

no problem