Question

9.55 x 10^24 molecules of CH3OH is how many grams?

Answer 1

use avogadro's number: \(\sf \color{red}{6.022 \times 10^{22}\frac{mole}{molecule}}\)

Answer 2

sorry, 23rd power, not 22.

Answer 3

^he's right. \(\sf moles=\dfrac{molecules}{Avogadro's~number}\)

Answer 4

Thank you!

Answer 5

It's not \(6.022*10^{23} \dfrac{\text{mole}}{\text{molecule}}\)!

It is \(6.022*10^{23}\dfrac{\text{<constituent particle>}}{\text{mole}}\); in this case the constituent particle is a molecule.

\[1 \text{ mole} * 6.022*10^{23}\dfrac{\text{molecule}}{\text{mole}} = 1 \cancel{\text{ mole}} * 6.022*10^{23}\dfrac{\text{molecule}}{\cancel{\text{mole}}}\]\[=6.022*10^{23}\text{ molecule}\]

Make a point of using the units correctly in all of your work and they will help you find or prevent many errors, especially in problems containing unit conversions.