Question

The velocity of an object increases from –10 m/s to –15 m/s in 2.0 s. What is the average acceleration of the object?


+2.5 m/s2


–2.5 m/s2

+12.5 m/s2


–12.5 m/s2

Answer 1

\[Acceleration = \frac{ \Delta V }{ \Delta t }\]

Answer 2

WHAT DOES THAT MEAN?

Answer 3

v divided by t?

Answer 4

delta V = final velocity - initial velocity
Delta T = time difference.

Answer 5

O.O

Answer 6

Did u get it ? Substitute and get the answer !!!

Answer 7

I dont understand anything

Answer 8

Do u understand the question ?

Answer 9

no

Answer 10

Haven't u learned this lesson at school ?

Answer 11

I go to online school and its harder to understand

Answer 12

q.q

Answer 13

@TorilovesVampires

Answer 14

@countonme123

Answer 15

okai
Acceleration is the rate of change of velocity.
Velocity is the rate of change of speed.
We do have equations for acceleration.
But if we are asked to find the average acceleration then we use only the below equation
\[Average acceleration = \frac{ Final velocity - initial velocity }{ time difference}\]

Answer 16

Here the final velocity is -15ms^-1
Initial velocity is -10ms^-1
and the time difference is 2s
now substitute and see

Answer 17

how would I do that?

Answer 18

\[Acceleration = \frac{ -15 - (-10) }{ 2 } = \frac{ -5 }{ 2 } = -2.5ms ^{-1}\]

Answer 19

thnk u

Answer 20

no probleem.