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Mathematics 56 Online
OpenStudy (anonymous):

What coordinate for F would make triangle ABC and triangle DEF congruent?

OpenStudy (anonymous):

OpenStudy (anonymous):

A) (-2,4) B) (-2,3) C) (-3,3) D) (-3,4)

OpenStudy (anonymous):

i believe that the answer is B , but that is just because i looked at the graph. its like an overlapping reflection, correct? i need help, i need someone to walk me through this . is there like, a formula? the lesson shows me this formula but its not clear on how to use it. \[\sqrt{(y1-y2)^2+ (x1-x2)^2}\]

OpenStudy (anonymous):

anone wanna assist me please? i wanna learn how to do this myself :(

OpenStudy (anonymous):

@ParthKohli @pooja195 @Data_LG2

OpenStudy (anonymous):

@hartnn @nincompoop @Abhisar

OpenStudy (anonymous):

@misty1212

OpenStudy (baru):

that formula you have typed out, do you know what it's for?

OpenStudy (anonymous):

@baru i THINK its to find the distance between two points, the lesson doesnt get detailed in it though :( they just start using it through examples

OpenStudy (baru):

you are right, its for the distance between two points. for two triangles to be congruent, the sides of the triangles should have equal lengths

OpenStudy (baru):

if you say triangle ABC congruent to DEF it means AB=DE BC=EF AC=DF

OpenStudy (baru):

with me so far?

OpenStudy (anonymous):

yes :)

OpenStudy (anonymous):

so how would i calculate f using the formula? would i use the distance between BC or Ac to find F or?...

OpenStudy (baru):

yeah..that would be the right way, but rather than solve for the co-ordinates of F, you are given several options for F, just substitute them and find EF and DF, see which one is equal to BC,AC

OpenStudy (anonymous):

so i use my options for F? and place them in the formula? im sorry if i dont quite understand, im a slow thinker in the morning :(

OpenStudy (baru):

yeah, exactly

OpenStudy (baru):

find the lengths EF and DF for each of the options, compare with the lengths AC and BC

OpenStudy (anonymous):

but how will i know it is right?

OpenStudy (anonymous):

@baru

OpenStudy (anonymous):

oh wait i THINK i understand, if they have the same result as the sides of the congruent triangle thats already there (abs) ?

OpenStudy (anonymous):

*c

OpenStudy (baru):

you have to do it for each option. only one option will give you EF=AC and DF=BC (you have to find lengths AC and BC as well)

OpenStudy (anonymous):

so i go all around? ok so first i find EF=AC right?

OpenStudy (baru):

first calculate AC and BC and write it down. then find EF for each option, see which one matches the value for AC that you just wrote down

OpenStudy (anonymous):

ok let me find AC and BC first

OpenStudy (anonymous):

@baru can you help me place the points into the formula? A = (1,-1) C= (2,3) B= (-1,2) C= (2,3)

OpenStudy (baru):

\[AC = \sqrt{(1-2)^2 + (-1-3)^2}\]

OpenStudy (baru):

\[BC = \sqrt{(-1-2)^2 + (2-3)^2}\]

OpenStudy (anonymous):

@baru but how did you place them? like which value was x1 x2 and y1 y2 ?

OpenStudy (baru):

oh...ok. wait. neglect what i typed just above, i have reversed the formula you gave(but it doesn't really matter). ill type it in detail, wait

OpenStudy (baru):

umm... how did you get A=(1,-1) ??

OpenStudy (anonymous):

i looked at the graph to see where the point is, did i saw it wrong? omg let me see haha

OpenStudy (anonymous):

is it (1,0)?

OpenStudy (baru):

yep :)

OpenStudy (baru):

so if you want to find the length AC then think of A =(x1,y1) and C=(x2,y2)

OpenStudy (baru):

so, x1=1 and y1=0 x2=2 and y2=3

OpenStudy (anonymous):

ohhhhhh kk hha now ill find AC

OpenStudy (anonymous):

i got 10 for AC

OpenStudy (anonymous):

AM I RIGHT? @baru

OpenStudy (anonymous):

lol i wanna make sure

OpenStudy (anonymous):

i have a feeling i am doing it wrong

OpenStudy (anonymous):

or is everything supoosed to stay in the sqr root ?

OpenStudy (anonymous):

so its supposed to be the sqr root of 10?

OpenStudy (anonymous):

so2 is my answer?

OpenStudy (baru):

yep, AC is square root of 10.

OpenStudy (anonymous):

so then i find BC?

OpenStudy (baru):

not necessary, option 2 is the only one which gives you EF= square root of 10

OpenStudy (baru):

did you try finding EF for all the options?

OpenStudy (anonymous):

what do you mean?

OpenStudy (baru):

i'm sorry i meant DF

OpenStudy (baru):

we established that for the two triangles to be congruent, length AC = length DF

OpenStudy (baru):

you have found that the length AC is square root of ten. the question gives you several options for the co-ordinates of F. so find the length DF for each of the options, and see which one gives you square root of 10

OpenStudy (anonymous):

ohhhhhhhhhhhhhhhhhhhhhh ok ok ok so i can test B and see if it gives me squeare rot of 10? and if it does it means that my answer is correct? but if it isnt i keep testing the other options until it matches square root of 10?

OpenStudy (baru):

what do you mean "so i can test B' ?

OpenStudy (anonymous):

option b for F

OpenStudy (baru):

oh..lol. Yep, you are absolutely right then

OpenStudy (anonymous):

yay! lol

OpenStudy (anonymous):

kk ima test it

OpenStudy (baru):

alright

OpenStudy (anonymous):

@baru i got the square root of ten aswell!~ does this mean B is my answer? :)

OpenStudy (baru):

yup

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