Question

How many moles of CaO form when 98.60 g CaCO3 decompose

Answer 1

\[CaCO _{3} ---> CaO + CO _{2}\]
as we can see the no. of moles of CacO3 = no. of moles of CaO
so it's just the matter of finding the no. of moles of CaCO3 right?
we know no. of moles = mass divided by the molar mass
Molar mass of CaCO3 = 100gmol^-1
\[moles = \frac{ 93.5g }{ 100gmol ^{-1} } = 0.935g\]