Question

Solve x2 − 5x + 1 = 0 using the quadratic formula.

Answer 1

step one is to -1 by both sides?

Answer 2

now just use the quadraitc formula

Answer 3

no**

Answer 4

you already know the formula
so just plugin a ,b ,c values

Answer 5

yeah but first -1 to the 1 and 0 go first dont they i have to simplify them.

Answer 6

comparing your equation with the general quadratic equation:
\[a{x^2} + bx + c = 0\]
we get:
a=1, b=-5, and c=1
now, please apply this formula:
\[x = \frac{{ - b \pm \sqrt {{b^2} - 4 \times a \times c} }}{{2 \times a}}\]

Answer 7

no quadratic equation should be in standard form \[\huge\rm Ax^2+Bx+C=0\]
equal to zero

Answer 8

that was for completing the square method
but when we use quadratic formula we ned `standard form`

Answer 9

ok

Answer 10

so what is the standard is it like ... idk actually

Answer 11

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
no quadratic equation should be in standard form \[\huge\rm Ax^2+Bx+C=0\]
equal to zero
\(\color{blue}{\text{End of Quote}}\)
^^that's the standard form

Answer 12

where
a=leading coefficient
b=middle term
c=constant term

Answer 13

now just plugin a ,b, c values into the quadratic formula

Answer 14

ok

Answer 15

writing all these down just in case your wondering... very helpful info for big exam EOC..

Answer 16

that's Awesome take ur time write theses down and practice as much as u can

Answer 17

k so what do i next because i wasn't sure...

Answer 18

did you substitute a ,b c for their values ?

Answer 19

a is x^2 right ?

Answer 20

and b is 5x?

Answer 21

no just the coefficient not the variable

Answer 22

look at the Michele'z comment
a=1
bec x^2 is same as 1x^2

Answer 23

so 5 since its not a variable?

Answer 24

/so your saying 1^2? i dont get how thats possible...

Answer 25

yes 5 is b

Answer 26

there is invisible one at front of x^2
x^2 is same as 1x^2 so leading coefficient is one

Answer 27

i'm not saying x =1
leading coefficient is one

Answer 28

\[\huge\rm \color{red}{1}x^2+\color{blue}{5}x+\color{green}{1}=0\]
\[\huge\rm \color{ReD}{A}x^2+\color{blue}{B}x+\color{green}{C}=0\]

Answer 29

alright

Answer 30

oky now just plugin

Answer 31

k thanks i gtg thanks for your help. :D