Can someone help me solve this? Not looking for an answer, just an explanation! :) This is a Compound Interest Formula, I'm being asked to solve for the Interest Rate (represented by r). 2,147.39 = 1,852.1(1+(r/12))^60 I don't know how to isolate r. Any help is greatly appreciated It's Advanced Algebra with Financial Applications.
\[2,147.39 = 1,852.1(1+\frac{ r }{ 12 })^{60}\]
\[[(2147.39/1852.1)^\frac{ 1 }{ 60 } - 1] \times 12\] you will need a calculator
Can you explain the steps involved? I have a calculator. I want to understand how to do that.
I never learned how to deal with exponents in equations, and my teacher isn't providing assistance.
you do not know how to get further than this, am i right \[2147.39/1852.1 = (1+ r/12)^6\]
sorry the exponant is 60
I can't eliminate the exponent.
I don't know how to do the converse of the exponent to the other side of the equation.
the trick is: you are allowed to "raise" both sides of the eqation to the same power
?
Ohhh I think I know what you mean Tell me if this is right? (2,147.39*1,852.1)^60 = (1+r/12)^60
not quite: (2,147.39/1852.1)^(1/60) = ((1+r/12)^60)^(1/60) i'm sorry that must be quite hard to read
i'll explain it differently
do u know what it means when I say "square both sides of the equation?" (talking in genral, not this problem)
Yes a^2 = a^2
do you understand if I say "take the square root of both sides"
Yes \[\sqrt{a} =\sqrt{a}\]
now what you should undertand is : \[\sqrt{x+y} = (x+y)^{1/2} \] they mean the same thing
Okay
in this question (i'm simplifying) its something like \[x+y= (a+b)^{60}\]
and i'm asking you to take the "sixtieth root on both sides"
\[(x+y)^{1/60}=((a+b)^{60})^{1/60}\]
x+y^(60/1) = (a+b)^60)^60/1
Err yeah 1/60 Sorry typo
not 60/1 its 1/60 square root: 1/2 sixtieth root: 1/60
oh lol ok
now use the rule \[((a)^{m})^n= (a)^{m \times n}\]
So 1.1594 ^(1/60) = ((1+r/12)^60)^(1/60)
yep
THANK YOU SO MUCH!!! Are you a Senior in HS?
nope...college
Awesome! Best of luck to you :) Thanks again!
sure :)
you too
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