Question

5 combination 2

Answer 1

like this

Answer 2

?

Answer 3

if yes then use the formula \[\huge\rm ^nC_r= \frac{ n! }{ r!(n-r)! }\]

Answer 4

k one sec

Answer 5

\[\frac{ 5! }{ 2! (5-2)! }=\frac{ 1*2*3*4*5 }{ 1*2(3)! }\]

Answer 6

looks good

Answer 7

\[\frac{ 120 }{ 6! }\]

Answer 8

how did you get 6! ?

Answer 9

you can't multiply 2 with 3!
3! is 3 times 2 times1
so 1 times 2 (3 times 2)

Answer 10

1*2(3)!

Answer 11

\[2(3)!=2(3 \times 2 \times 1)\]

Answer 12

so 120/12

Answer 13

=10

Answer 14

right

Answer 15

thx

Answer 16

np,good work!

Answer 17

btw, it is better to do it this way:
\[ \frac{5\cdot 4 \cdot 3!}{2 \cdot 3!} \]
notice that the 3! cancels, you have have 5* 4/2 = 5*2 =10
this way you don't have to calculate huge numbers.