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Mathematics 18 Online
OpenStudy (anonymous):

Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2. Find g(f(x)). Show each step of your work. Please don't just give the answer! Walk me through it. Thank you!

Vocaloid (vocaloid):

g(f(x)) means take f(x) and substitute it for x in g(x)

Vocaloid (vocaloid):

g(x) = x^2 - 2 g(f(x)) = f(x)^2 - 2 = (4x^2 + x + 1)^2 - 2 finish by expanding

OpenStudy (jdoe0001):

actaully it was the other way around... anyhow =)

OpenStudy (anonymous):

i'm confused now. what do you mean the other way around?

OpenStudy (jdoe0001):

\(\bf f(x) ={\color{brown}{ 4x^2+x+1}}\qquad g(x)={\color{black}{ x^2-2}} \\ \quad \\ g(\ {\color{brown}{ f(x)}}\ )=({\color{brown}{ f(x)}})^2-2\)

OpenStudy (jdoe0001):

expand as Vocaloid suggested

OpenStudy (anonymous):

okay... so g(f(x)) = (4x^2 + x + 1)^2 - 2. I'm probably way off, but 16x^4 + x^2 + 2 - 2.

OpenStudy (jdoe0001):

just bear in mind that \(\bf (4x^2 + x + 1)^2 \implies (4x^2 + x + 1)(4x^2 + x + 1)\)

OpenStudy (anonymous):

so was I right? I just had to take away the -2 at the end?

OpenStudy (anonymous):

What are the steps I have to take? Maybe I can figure it out if you tell me the steps to get the answer. Thanks so much for helping me by the way.

Vocaloid (vocaloid):

not quite (4x^2 + x + 1)^2 = (4x^2 + x + 1)*(4x^2 + x + 1) use foil to expand

OpenStudy (anonymous):

Okay. Foil = First, outer, inner, last?

Vocaloid (vocaloid):

yes

Vocaloid (vocaloid):

we also have a middle term in this case, x

OpenStudy (anonymous):

a sec. pls

OpenStudy (anonymous):

so it would be x squared in the middle

Vocaloid (vocaloid):

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Vocaloid (vocaloid):

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Vocaloid (vocaloid):

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