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Mathematics 10 Online
OpenStudy (anonymous):

hey @parthkohli

OpenStudy (anonymous):

when i say 30 i mean 40

Parth (parthkohli):

what does "reducing the length of the curve" mean? I mean you can draw the shortest possible path from (10,10) to (30,0) that also happens to be a straight line.

OpenStudy (anonymous):

yea but it needs to be smooth

OpenStudy (anonymous):

so polynomial

Parth (parthkohli):

what does that mean? a linear function is a polynomial too. what exactly do you mean by smooth?

OpenStudy (anonymous):

mena no rough edges and its curve

OpenStudy (anonymous):

like continuous function

Parth (parthkohli):

ahhh, better.

OpenStudy (anonymous):

is there function that looks like the black line i drew

Parth (parthkohli):

so you need a polynomial function that makes a smooth transition and is also the shortest

OpenStudy (anonymous):

so it has curve to smothly attach to another track but at the smae shorter length

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

but at the same time *

Parth (parthkohli):

what's the context of this question? it's really specific

OpenStudy (anonymous):

i have done the question let me send the link

OpenStudy (anonymous):

but what i am trying to figure out is the shorter length than this

Parth (parthkohli):

sorry, my OS stopped working.

OpenStudy (anonymous):

so on xy plane i want a function that give me length <27.37

OpenStudy (anonymous):

|dw:1443516744812:dw|

OpenStudy (anonymous):

ok

Parth (parthkohli):

You're permitted to use calculators right?\[g(x) = ax^4 + bx^3 + cx^2 + dx + e\]\[10^4 a + 10^3 b + 10^2 c + 10 d + e = 10\]\[30^4 a + 30^3 b + 30^2 c + 30 d + e=0\]\[\int_{10}^{30} g(x)dx=200\]\[4a(10)^3 + 3b(10)^2 + 2c(10) + d(10) =0\]Now the last one is tricky.

OpenStudy (anonymous):

yess

Parth (parthkohli):

You know how to calculate arc length using integrals right?

OpenStudy (anonymous):

yea but i use wolfram alpha normaly u mind using it sending the link plz

Parth (parthkohli):

Because you really are looking to minimise arc-length given the above constraints.

OpenStudy (anonymous):

ok wait do i do the same steps as i did for my previous function find a,b,c,d

OpenStudy (anonymous):

and then put them in an expression and use arc length to get length

Parth (parthkohli):

I think Wolfram is gonna have some good fun with this one.

OpenStudy (anonymous):

heheh

Parth (parthkohli):

Here, you have a, b, c, d and e.

OpenStudy (anonymous):

yea kinda forgot about e

OpenStudy (anonymous):

thank you so much for ur help

Parth (parthkohli):

I'm curious to see how you'll input so much into Wolfram. It's scary.

OpenStudy (anonymous):

what if i find an expression then too

Parth (parthkohli):

sorry, the last equation is\[4a(10^3) + 3b(10^2 ) + 2c(10) + d = \color{red}1\]

OpenStudy (anonymous):

ok

Parth (parthkohli):

wow the expression is way too long... you'll have to be subscribe to pro

OpenStudy (anonymous):

i have subscribe pro

Parth (parthkohli):

wow, cool.

OpenStudy (baru):

@ParthKohli for arguments sake, (specifics not necessary) i would write the function for arc length squared lets call it L=f(a b c d e) now what?to minimize, we need to substitute variables in terms of each other so that they represent their inter-dependencies right? how will you do that? you have four other equations ? or am i way off, and talking crap?

Parth (parthkohli):

yes - we have four equations. in the arc length function, we'll eliminate four variables and will be left with a function that is in terms of only one variable.

OpenStudy (baru):

is that a general thing, as in if there are n unknowns and (n-1) equations we can bring it down to 1 variable?

Parth (parthkohli):

I suppose. Let's take a smaller example.\[f(x,y,z) = x+y-z\]\[x=y+1\]\[z = -x\]\[f(x,y,z) =x+(x-1) - (-x) = 3x - 1\]

Parth (parthkohli):

Three variables, two equations. Now we can minimise the function with one-variable very easily.

OpenStudy (baru):

ok. thanks :)

OpenStudy (baru):

@ParthKohli one other thing, i get why you have picked an equation with 5 unknowns since we have 5 pieces of information, but the equation could just as easily been \[ax^7 + bx^6 +cx^5 +dx +e\] or something else equally arbitrary so why specifically have you chosen the one that you have?

Parth (parthkohli):

that is a very good observation, one that I did give some thought to but skipped. unfortunately, it may be impossible to find *the* polynomial that satisfies the above constraints because the degree may go as high as... anything we want it to reach. the degree-seven polynomial you wrote may not be the best degree-seven polynomial to satisfy the conditions because it's missing some terms and unless we're sure while solving for the seventh-degree that those terms turn out to be zero, we'll never be sure. so choose a degree-four polynomial adds certainty to what we get - we can be sure that we'll get the best fourth-degree polynomial. of course there are polynomials much better than that one, but we can only go as far as we can look.

Parth (parthkohli):

ultimately, we're looking for a polynomial that resembles a straight-line the most in the region x = 10 to x = 30, so we can add as many terms as we like, but we can't go that far - can we?

OpenStudy (baru):

ah..makes sense. thanks a lot!!

Parth (parthkohli):

by the way, we still can approach this problem through multivariable calculus for polynomials that have more terms than five. that way, we can get an even closer polynomial.

OpenStudy (anonymous):

hey its not making sense

Parth (parthkohli):

thanks for the question - I really had to think about it to come up with an answer.

OpenStudy (anonymous):

5 variables how do i get values for 5 unknown variable

Parth (parthkohli):

plug it into WolframAlpha

OpenStudy (anonymous):

i only have 4 equation

OpenStudy (anonymous):

i found a ,b, c ,d but not e

Parth (parthkohli):

were you able to find a, b, c, d in terms of e?

OpenStudy (anonymous):

\[0.0001852x ^{4}-0.01246x ^{3}+0.2076x ^{2}-0.01555x+e\]

Parth (parthkohli):

wait what? you were able to uniquely determine a, b, c, d?!

OpenStudy (anonymous):

from here

Parth (parthkohli):

it's not a 4x4 equation so

OpenStudy (anonymous):

yea i thought so help plz

Parth (parthkohli):

plug the stuff into Wolfram and it should give you all other variables in terms of one variable

OpenStudy (baru):

@ayeshaafzal221 where did you find this question?

OpenStudy (anonymous):

it didnt

OpenStudy (anonymous):

its my practise question for exams

Parth (parthkohli):

what did it return?

Parth (parthkohli):

you don't have a Wolfram pro subscription do you?

OpenStudy (anonymous):

on my ipad yes

OpenStudy (anonymous):

even on my ipad not working

Parth (parthkohli):

there's this data entry or something feature which you can use

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

or u know the values i have found cant i just sub it into any equation and get the e value

Parth (parthkohli):

no, you can't do that. it's not a 4x4 equation so you most likely input the wrong equations.

OpenStudy (anonymous):

yea true i am gonna go old fashion , and do em manually

OpenStudy (baru):

@ParthKohli , when you say multi-variable calculus approach: are you talking about Lagrange multipliers?(i've just reached this topic)

Parth (parthkohli):

Obviously. Yes.

OpenStudy (baru):

alright..thanks

OpenStudy (anonymous):

@ParthKohli srry i am disturbing u again when u say we have five variables and one of them was minimum arc length what do u mean?

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