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I don't understand this :( Suppose (-3, 5) is a point on the graph of y = g(x) What point is on the graph of y = -3g(x-4) + 3 What point is on the graph of y = g(3x+9)
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@imqwerty
Well the line has a horizontal shift to the right 4 units so this says (-3,5) turns to (1,5)
then has slope of -3
which becomes (-3,-15) then shifts up 3 units upward, (-3,-12)
i might be wrong
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g(x)=y and u got- y = -3g(x-4) + 3 y-3=-3g(x-4) (y-3)/(-3) =g(x-4) compare this with g(x)=y we know that in this^ when x=-3 y=5 so compare g(x)=y with (y-3)/(-3) =g(x-4) x-4=3 x=7 (y-3)/(-3) =5 y-3=-15 y=-12 so (7,-12) do the same with the second one :)
it should be (-3,12) your step with x-4=3 should actually be x-4=-3
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