Find f(x) and g(x) so that the function can be described as y = f(g(x)).
y = two divided by x squared + 9
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OpenStudy (anonymous):
@Nnesha plssss
OpenStudy (anonymous):
@agent0smith
Nnesha (nnesha):
\[y=\frac{ 2 }{ x^2 }+9\] like this ?
OpenStudy (anonymous):
yes
Nnesha (nnesha):
f(g(x)) meaning substitute x for g(x) function
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OpenStudy (anonymous):
yeah, and then you simplify?
Nnesha (nnesha):
right but this one is backwardz u have to find f(x) and g(x) from\[y=\frac{ 2 }{ x^2 }+9\]
OpenStudy (anonymous):
is f(x) = 2/x + 9 and g(x) = x^2
Nnesha (nnesha):
hmm
Nnesha (nnesha):
could be this \[\frac{ 2 }{ x^2 } +9 \]
g(x) =x
hmmm
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OpenStudy (anonymous):
yeah do both work?
OpenStudy (anonymous):
i got it right, it was whtai wrote :)
OpenStudy (anonymous):
i have one more coudl you help wiht that?
Nnesha (nnesha):
hmm okay i'll try
OpenStudy (anonymous):
ok thanks
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OpenStudy (anonymous):
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
f(x) = Quantity x plus four divided by six and g(x) = 6x - 4
OpenStudy (anonymous):
f(x) = x+4 / 6
g(x) = 6x - 4
Nnesha (nnesha):
alright first try f(g(x))=x
substitute x for g(x) function \[\huge\rm f(\color{ReD}{g(x}))=\frac{( \color{ReD}{6x-4} )+ 4}{ 6 }\] now solve right side
is it equal to x ??
OpenStudy (anonymous):
yes
Nnesha (nnesha):
alright now 2nd one g(f(x) ) is this equal to x ?
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OpenStudy (anonymous):
umm
OpenStudy (anonymous):
yes?
Nnesha (nnesha):
i don't know it yet
Nnesha (nnesha):
substitute x for f(x) function into f(x)
OpenStudy (anonymous):
ok
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Nnesha (nnesha):
\[\huge\rm g(\color{ReD}{f(x)})=6\color{ReD}{x}-4\]
replace x with (x+4)/6
OpenStudy (anonymous):
6(x+4)/6 -4
Nnesha (nnesha):
right \[6(\frac{x+4 }{ 6 })-4\]
is it equal to x ?
OpenStudy (anonymous):
yers
Nnesha (nnesha):
both are equal that shows both are inverse of each other
f(g(x)) = g(f(x))
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