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|dw:1443649213389:dw|
whats the area
\[x ^{2}+3x-40 ft\]
ft ^2
The area of any triangle is calculated by: \[A _{\triangle}=\frac{ b.h }{ 2 }\] This means, base time height divided by two. Since in the excercise we are given the area \(x^2+3x-40\) and we know that the base is \(x+8\), we can then use the formula above by replacing the data: \[x^2+3x-40=\frac{ (x+8)(h) }{ 2 }\] Now, it's just a matter to solve for "h".
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So, \[(x-5)(x+8)=\frac{ (x+8)(h) }{ 2 }\] Now, what do i do.
Well, now try to isolate that h on any side of the "=" sign.
does the (x+8) cancel out?
@owlcoffee
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