Question

Find an equation of the tangent line to the curve at the given point y=sqrt{x} (1,1)

Answer 1

\[y=\sqrt(x) \]

Answer 2

Given point (1,1).

Answer 3

First step differentiate

Answer 4

We do this because we know f'(1) will give us the slope of the line that is tangent to the curve y=sqrt(x) at (1,1)

Answer 5

point slope form for a line that contains the point (a,b) is
y-b=m(x-a)
where m is the slope...
so here you will have:
y-f(1)=f'(1)(x-1)
where f(1)=sqrt(1)=1 <--this was actually given
so you have
y-1=f'(1)(x-1)
only work for you to do is to find f'(1) and replace f'(1) here

Answer 6

Alright, thank you very much!

Answer 7

np