Question

Solve the Quadratic:

3x^2+10x-8=0

Answer 1

\(\large\color{black}{ {\rm Discriminant}=\sqrt{b^2-4(a)(c)} \\[1.2em]=\sqrt{10^2-4(3)(-8)}=\sqrt{100-(-96)} =\sqrt{196}=14}\)

Answer 2

Dont you have to divide it by 2a?

Answer 3

You can either solve your equation using the *quadratic formula* (I have calculated the discriminant for you)
OR, you can factor, because the discriminant is an integer and thus your quadratic can be factored.

Answer 4

I tried factoring but I got confused

Answer 5

*QUADRATIC FORMULA*
\(\normalsize\color{ slate }{\Huge{\bbox[5pt, lightcyan ,border:2px solid black ]{ \LARGE{x=~} \huge{ \frac{-\color{magenta}{b} \pm\sqrt{ \color{magenta}{b} ^2-4 \color{blue}{a} \color{red}{c}}}{2 \color{blue}{a}} }~ }}}\)

when the equation is \(\LARGE\color{black}{ \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0 }\)

Answer 6

Could you help me with factoring?

Answer 7

you already know that:

\(\large \displaystyle x=\frac{-\color{magenta}{10} \pm14}{2 \color{blue}{(3)}}\)

Answer 8

14 is the value of that entire root, which I calculated in the beginning, and you know that in your case,
*a=3* and *b=10*

Answer 9

so is there two answers?Because +- 14

Answer 10

yes, and they are simplifiable.

Answer 11

you can do the rest....

Answer 12

2/3 and -4?

Answer 13

yes, right

Answer 14

thanks