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Which of these equations are linear equations?
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OpenStudy (vikstar2.0):
what are the equations
OpenStudy (anonymous):
\[\frac{ x }{ 4 } - \frac{ y }{ 3 } = 1 \]
OpenStudy (vikstar2.0):
thats it or is there more
OpenStudy (anonymous):
there is more
OpenStudy (anonymous):
just wait im typing the equation
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OpenStudy (anonymous):
\[\frac{ 5 }{ x } - \frac{ 2 }{ y } = 7\]
OpenStudy (anonymous):
So is it:
a)the first one
b)the second one
c)or both
OpenStudy (vikstar2.0):
@Hero @LynFran
OpenStudy (anonymous):
@vikstar2.0
OpenStudy (vikstar2.0):
i think it is both
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OpenStudy (anonymous):
@Hero
OpenStudy (vikstar2.0):
but most likely the first one
OpenStudy (anonymous):
i need the work though
OpenStudy (anonymous):
Anybody who can help me????
OpenStudy (anonymous):
@ayeshaafzal221
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OpenStudy (anonymous):
@SolomonZelman
OpenStudy (vikstar2.0):
how am i supposed to show the work?
OpenStudy (anonymous):
any equation in the form of y=mx+b is linear
OpenStudy (anonymous):
i thought it was supposed to be ax+by=c
OpenStudy (anonymous):
anyways could u pls explain
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OpenStudy (anonymous):
@Hero
hero (hero):
Try re writing both in linear form.
OpenStudy (anonymous):
For the first one, I think it is 3x-4y=12, but I'm still not that sure how I got 12.
hero (hero):
.Please show the work you did to get that.
OpenStudy (anonymous):
I cross-multiplied:
3(x) and 4(y), which gave me 3x-4y. And then I guess I multiplied the 3 and 4 and got 12.
So 3x-4y=12
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OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
Where did @Hero go?
OpenStudy (anonymous):
Aw man, he's offline. :(
OpenStudy (anonymous):
@mathmate
OpenStudy (anonymous):
@dan815
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OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
@emily_wilson
OpenStudy (anonymous):
@SolomonZelman
pooja195 (pooja195):
Is there a way you can post the questions and options in one post?
OpenStudy (anonymous):
I do not know. Do you want the options?
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OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
@Kate_J2002
hero (hero):
The approach you took is not "algebraic" and would be considered an incorrect approach.
OpenStudy (anonymous):
Oh sorry could you please help me to do it the correct way?
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hero (hero):
You don't cross multiply The difference of two fractions.
OpenStudy (anonymous):
Oh ok.
hero (hero):
Multiply both sides of the equation by the LCD
OpenStudy (anonymous):
You mean the Least Common Denominator?
hero (hero):
Exactly.
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OpenStudy (anonymous):
Ok let me try. Don't leave, please.
OpenStudy (anonymous):
But there are 2 fractions on one side of the equation, so how will I find the LCD?
OpenStudy (anonymous):
I'm sorry for being so dumb.
OpenStudy (anonymous):
Are you there @Hero ?
OpenStudy (anonymous):
@pooja195
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hero (hero):
I'M here. The LCD is twelve. you should watch a tutorial on how to find the LCD of two fractions going forward though
OpenStudy (anonymous):
Your talking about the first equation, right?
hero (hero):
Correct.
OpenStudy (anonymous):
Ok so I should multiply 12 with both the fractions and 1, right?
hero (hero):
Correct
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OpenStudy (anonymous):
Ok.
hero (hero):
Don't forget to cross cancel where possible.
OpenStudy (anonymous):
So:
12x/4 - 12y/3 = 12
3x - 4y = 12
hero (hero):
Correct
hero (hero):
So you know the first equation is linear since it has the general linear form.
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OpenStudy (anonymous):
OK NOW I GET IT! Isn't 3x - 4y = 12 a linear equation in standard form, which is
ax - by = c
hero (hero):
Now try writing the second equation In the same form.
OpenStudy (anonymous):
Ok just wait. Please don't leave.
OpenStudy (anonymous):
So 10 is the LCD for the second equation, right?
hero (hero):
Tell me what is in the denominators of the fractions of the Second equation?
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OpenStudy (anonymous):
x and y.
hero (hero):
Explain how 10 Can be the LCD of x and y.
OpenStudy (anonymous):
OH WAIT SO YOU CANNOT FIND THE LCD FOR THE SECOND EQUATION BECAUSE THEY'RE VARIABLES. So that means it is NOT A LINEAR EQUATION, right?
OpenStudy (anonymous):
Or am I wrong?
hero (hero):
Actually, there IS an LCD for denominators x and y.
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OpenStudy (anonymous):
Is it xy
hero (hero):
You find it the same way you found the LCD of 3 and 4
hero (hero):
Correct
OpenStudy (anonymous):
Yay! But the second equation isn't a linear equation, right?
hero (hero):
You have to SHOW that it isn't
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OpenStudy (anonymous):
I don't actually know how to do that.
OpenStudy (anonymous):
Please help me out.
hero (hero):
Try to write it in linear form. You already found the LCD. Remember what to do afterwards?
OpenStudy (anonymous):
OH YEAH! Just give a minute. I'll solve it out. Just stay there.
OpenStudy (anonymous):
So:
5xy/1x - 3xy/1y = 7xy
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hero (hero):
Cross cancel
OpenStudy (anonymous):
What are those?
hero (hero):
Factors of one that allow you to Simplify expressions.
OpenStudy (anonymous):
Oh ok.
hero (hero):
Cross cancel
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OpenStudy (anonymous):
So:
5xy - 3xy = 7xy
hero (hero):
You have good intention but that is not the correct Simplification.
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
How do I do that?
hero (hero):
What does x/x =1 mean to you?
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OpenStudy (anonymous):
1/1=1
hero (hero):
Well that would imply that x=1 but x is a variable
OpenStudy (anonymous):
I'm confused.
hero (hero):
Basically for any fraction, if you have a factor in the numerator and the same factor in the denominator of a fraction, then the factors cancel to just 1
hero (hero):
The factors together Cancel to get 1 but a factor by itself does not equal one.
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