Question

SHINY MEDALS!!!!!!

Answer 1

If (70)x = 1, what are the possible values of x? Explain your answer.

Answer 2

sorry this is the q- If (7^0)^x = 1, what are the possible values of x? Explain your answer.

Answer 3

@pooja195 @Kate_J2002 @blackfireskull @Nnesha

Answer 4

answers is one.

Answer 5

thank u

Answer 6

because... 7^0 = 1. if 1^x=1, then x has to be one

Answer 7

Wrong.

Answer 8

let me know if i was right

Answer 9

how so

Answer 10

?????

Answer 11

\[\huge\rm (anything)^0=1\] (expect 0^0 i guess )
\[\rm (nnesha)^0 =1~~~(x)^0=1~~~~~(HELPMEPLZ)^0=1\]

Answer 12

oh never mind it can be any positive whole number

Answer 13

so...it's 0?

Answer 14

because 1^3 and 1^100000 is always going to equal one @Compassionate

Answer 15

\[({70}^{0th})^x = 1\]\[1^\infty = 1\] Therefor, any number to the 1st power will be one.

Answer 16

thats not the question, its the one below it

Answer 17

Asumming it is a posivie, whole integer.

Answer 18

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[\huge\rm (anything)^0=1\] (expect 0^0 i guess )
\[\rm (nnesha)^0 =1~~~(x)^0=1~~~~~(HELPMEPLZ)^0=1\]
\(\color{blue}{\text{End of Quote}}\)
anything to the zero power equal to one
now first apply the exponent rule \[\large\rm (\color{ReD}{7^0})^x\]

Answer 19

so...@HELPMEPLZ!! it can be any positive whole number because one times itself equals one no mater how many times you multipy 1*1. right @Compassionate ?

Answer 20

therefor th e answer can be any positive whole number @HELPMEPLZ!!

Answer 21

More precise: \[\mathbb{Z}^+ \times (^0) [\times ({\infty+\mathbb{Z}^+})] = 1\]

Answer 22

thx ill close the question now

Answer 23

Which would be the definite, mathematical representation.

Answer 24

and remember the PEMDAS rule
Parentheses
and then exponent
good luck!