Help please.
holly wants to save money for an emergency. Holly invests $1,500 in an account that pays an interest rate of 6.75% . How many years will it take for the account to reach $7,300? Round to the nearest hundredth
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OpenStudy (anonymous):
A= P(1+r)^t is the equation
OpenStudy (anonymous):
@chris00
OpenStudy (anonymous):
@BlooooooBlahBLIIIIK
OpenStudy (anonymous):
now is the interest rate annually?
OpenStudy (anonymous):
It doesnt state if its annually or not
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OpenStudy (anonymous):
\[A=P \left( 1+r \right)^{t}\]
where P=$1500, r=0.0675 A=$7,300
OpenStudy (anonymous):
we need to find 't'
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Would it be 24.23??
OpenStudy (anonymous):
\[7300=1500\left( 1+0.0675 \right)^{t}\]
\[7300=1500\left( 1.0675 \right)^{t}\]
Dividing both sides by 1500,
\[\frac{ 73 }{ 15 }=1.0675^{t}\]
Taking the logarithm,
\[\ln \left( \frac{ 73 }{ 15 } \right)=tln \left( 1.0675 \right)\]
Making 't' the subject,
\[t=\frac{ \ln \left( \frac{ 73 }{ 15 } \right) }{ \ln \left( 1.0675 \right) }\]
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