Solve this equation for x. Round your answer to the nearest hundredth.
1= ln(x+8)
Use the property z=a^logaZ

Question

Solve this equation for x. Round your answer to the nearest hundredth. 
1= ln(x+8) 
Use the property z=a^logaZ

anonymous · Answer

applying that property, you know that: $e^{\ln x} = x$

.. for your question, change the bases into e on both sides, so it will look like this: 
$\sf \large e^1= e^{ln(x+8)}$

now simplify this using the property

anonymous · Answer

Im still confused...could you explain the process??

anonymous · Answer

if $\ln(\text{whatever})=1$ then $\text{whatever}=e$

anonymous · Answer

How do i go about finding the answer? I dont understand

anonymous · Answer

Would it be 2??

owlet · Answer

What is e^1?

anonymous · Answer

I dont know what e^1 is

owlet · Answer

then using the rule, what is e^ln(x+8) simplify to?

it is like z=a^log a z, 
a= e
z= x+8 , therefore, e^ln(x+8) is equal to?

owlet · Answer

any number raised by one will be equal to the number itself., so e^1 =e

anonymous · Answer

I still dont understand how to find the answer.

owlet · Answer

simplify the equation first before you can find the value of x

anonymous · Answer

Ok

owlet · Answer

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